It is given that in a group of 3 students, the probability of 2 students not having the same birthday is 0.992. What is the probability that the 2 students have the same birthday?
Solution:
We know the total probability of all outcomes is always 1.
So, the probability that 2 students have the same birthday is simply the complement of them not having the same birthday.
That is,
P(same birthday) = 1−P(not same birthday)
Given,
P(not same birthday) = 0.992
So,
P(same birthday) = 1 − 0.992 = 0.008