Exercise 1.1, 6

Explain why 7 × 11 × 13 + 13 and 7 × 6 × 5 × 4 × 3 × 2 × 1 + 5 are composite numbers

 

Solution:

Expression 1: 7 × 11 × 13 + 137

Factor out the common term

7 × 11 × 13 + 13 = 13 × (7 × 11 + 1)

Simplify the expression inside parentheses

7 × 11 + 1 = 77 + 1 = 78

13 × 78

Since 13 and 78 are both greater than 1, the number is composite.

Expression 2:  7 × 6 × 5 × 4 × 3 × 2 × 1 + 5

Recognize the factorial term

                                     7! + 5

where 7! = 7 × 6  × 5 × 4 × 3 × 2 × 1 = 504.

Factor out the common term

          7! + 5 = 5040 + 5 = 504

Check divisibility

Since 5045 can be factored as:

          5045 = 5 × 1009

where 5 and 1009 are greater than 1, this means 5045 is composite.

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