Exercise 1.1, 5

Check whether 6n can end with the digit 0 for any natural number n.

 

Solution:

Condition for a number to end in 0

A number ends in 0 if and only if it is divisible by 10, which means it must be divisible by both 2 and 5.

Prime Factors of 6n

6n = (2 × 3)n = 2n × 3n

  • The factorization shows that 6n consists of only powers of 2 and 3.
  • It does not contain 5 as a factor.
Checking for divisibility by 10
  • Since 6n is not divisible by 5, it can never be divisible by 10.
  • Therefore, 6n can never end with the digit 0 for any natural number n.
Final Answer:

            No, 6n cannot end with the digit 0 for any natural number n.

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