A die is thrown once. Find the probability of getting
(i) a prime number;
(ii) a number lying between 2 and 6;
(iii) an odd number.
Answer:
(i) Probability of getting a prime number at:
Prime numbers between 1 and 6 are 2, 3, and 5.
So, the favorable outcomes are {2, 3, 5}.
The total number of outcomes is 6 (since the die has 6 faces).
Thus, the probability is:
P(prime number) = Number of favorable outcomes / Total number of outcomes = 3/6 = ½
(ii) Probability of getting a number lying between 2 and 6:
The numbers between 2 and 6 are 3, 4, and 5.
The favorable outcomes are {3, 4, 5}.
Thus, the probability is:
P(between 2 and 6) = 3/6 = 1/2
(iii) Probability of getting an odd number:
The odd numbers on the die are 1, 3, and 5.
The favorable outcomes are {1, 3, 5}.
Thus, the probability is:
P(odd number) = 3/6 = ½